Question

factorise 27 x 3 + 3 + Z 3 minus x y z​

Answer 1

Answer:

27x

3

+y3z39xyz

=(3x)

3

+y3z39xyz

=(3x)

3

+y3z33×3x×y×z

using identity

a3

 

b3

 

c3

 

3abc=

 

(a+

 

b+

 

c)(a

2

+

 

b2

 

c2

 

ab−

 

bc−

 

ca)

Putting

a=

3x,b=

y,c=

z

=(3x+y+z)(9x

2

+y2z23xy−yz

Answer 2

Answer:

   

Step-by-step explanation: