Question

factorise 27 x cube + 64 y cube​

Answer 1

27x³+64y³

by using a³+b³=(a+b)(a²+b²-ab)

(3x)³+(4y)³= (3x+4y)[(3x)²+(4y)²-12xy]

= (3x+4y)(9x²+16y²-12xy) [required answer]

Hope it helps !!

thank you ★★

Answer 2

$27 {x}^{3} + 64 {y}^{3} \\ \\ ({3x})^{3} + ( {4y})^{3} \\ \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} ) \\ \\ (3x + 4y)(9 {x}^{2} - 12xy + 16 {y}^{2} )$