Question

factorise 27/x³-y³/64​

Answer 1

answer:

(3/x-y/4) (9/x^2+y^2/16+3y/4x)

step:

= 27/x^3-y^3/64

= (3/x)^3-(y/4)^3

= (3/x-y/4) {(3/x)^2+(y/4)^2+3/x*y/4}

= (3/x-y/4) (9/x^2+y^2/16+3y/4x)

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