Factorise: 27a^3+125b^3-c^3+45abc
Answers
Answered by
3
Answer:
27a ^{3} + 125b ^{3} - c ^{3} + 45abc
= 27a^{3} -c^{3} +125b^{3} + 45abc
= 1^3 [27a - c] + 5b [25b^2+9ac]
= (1^3+5b)(27a-c)(25b^2+9ac)
Similar questions