factorise 27a^3-2√2b^3
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From algebra we know that, a³ - b³ can be factorized as
a³ - b³ = (a -b)(a² +ab +by).
The given expression, can be written
A³ - 2√2 B³ =[ (A)³ -(√2 B)³] = (A - B√2)(A² + AB√2 + 2B)= (A -√2 B)(A² + √2 A B + 2 B²).
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