Question

factorise 27a^3+64 plz​

Answer 1

Answer:

${(3a)}^{3} + {4}^{3} \\ = (3a + 4)( {( 3a)}^{2} - (4)(3a) + {4}^{2} ) \\ = (3a + 4)( {9a}^{2} - 12a + 16)$