Question

Factorise 27a^6-(6+3c)^6 as difference of two squares or two cubes

Answer 1

Answer:

Hii,

Step-by-step explanation:

27a6 – (6+3c)6

To find: Factorise the difference of two squares or two cubes.

Solution: We know that x³ − y³ = (x − y) (x² + xy + y²)

Step 1: Write the given expression in terms of identity

(3a²)³ - ((6+3c)²)³

Step 2: Apply identity here x=3a², y=(6+3c)²

(3a²)³ – ((6+3c)²)³ = (3a² − (6 +3c)²)( -

Step 3: Apply identity x²-y²=(x+y)

(x-y)

here

x=√3a

y=6+3c

(3a²)³ − ((6+3c)²)³ = (√3a + (6 + 3c))(

or

(3a²)³ ((6+3c)²)³ = (√3a +6+3c)(√

Final answer:

Factorise the difference of two squares or two cubes are as shown

27a6 – (6+3c)6 = (√3a +6+3c)(√3a

Note*: Expression is corrected to make perfect cube or perfect square.

Hope it helps you...