Question

Factorise 27a cube+b cube+8c cube-18abc using identity​

Answer 1

Answer:

$27a {}^{3} + {b}^{3} + 8 {c}^{3} - 18abc \\ \\ = (3a + b + 2c)(9 {a}^{2} + {b}^{2} + 4 {c}^{2} - 3ab - 2bc - 6ac)$

Answer 2

Answer:

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