factorise ,27a³ + 125 b³
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Answer:
(27a³+125b³)=(3a)³+(5b)³
= using identify (x³+y³)=(x+y)(x²-xy+y²)
weget (3a+5b)(3a²+5b²-3a*5b)
(3a+5b)(9a²- 15ab+25b²)
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