Factorise 27a3+64b3 pls fast
Answers
Answered by
31
Factoring: 27a3+64b3
Theory : A sum of two perfect cubes, a³+ b³ can be factored into :
(a+b) • (a²-ab+b²)
Proof : (a+b) • (a²-ab+b²) =
a³-a²b+ab²+ba²-b²a+b³=
a³+(a²b-ba²)+(ab²-b²a)+b³=
a³+0+0+b³=
a³+b³
Check : 27 is the cube of 3
Check : 64 is the cube of 4
Check : a³ is the cube of a¹
Check : b³ is the cube of b¹
Factorization is :
(3a + 4b) • (9a² - 12ab + 16b²)
Theory : A sum of two perfect cubes, a³+ b³ can be factored into :
(a+b) • (a²-ab+b²)
Proof : (a+b) • (a²-ab+b²) =
a³-a²b+ab²+ba²-b²a+b³=
a³+(a²b-ba²)+(ab²-b²a)+b³=
a³+0+0+b³=
a³+b³
Check : 27 is the cube of 3
Check : 64 is the cube of 4
Check : a³ is the cube of a¹
Check : b³ is the cube of b¹
Factorization is :
(3a + 4b) • (9a² - 12ab + 16b²)
Answered by
0
Answer:
(3a+4) (9a2-12ab+16b2)
Step-by-step explanation:
=(3a) 3+(4b) 3
:-a3+b3=(a+b) (a2-ab+b2)
total answer is:-
=(3a+4) (9a2-12ab+16b2)//
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