Question

Factorise 27a3 − (b − c)3

Answer 1

Answer:

(3a-b+c)(9a²+3ab-3ac+b²-2bc+c²)

Step-by-step explanation:

= 27a³-(b-c)³

First we need to do the cubic form

Then, we need to apply the formula of a³-b³=(a-b)(a²+ab+b²)

= (3a)³-(b-c)³

= (3a-b+c)(9a²+3ab-3ac+(b-c)²)

= (3a-b+c)(9a²+3ab-3ac+b²-2bc+c²)

= (3a-b+c)(9a²+b²+c²+3ab-2bc-3ac)

Hence, the Factories of 27a³-(b-c)³ is (3a-b+c)(9a²+b²+c²+3ab-2bc-3ac)

Answer 2

Answer:

Step-by-step explanation:

We need to use the below formula to factorize:

$a^{3} - b^{3} = (a -b)(a^{2} + ab + b^{2} )$

The question is

$27a^{3} - (b-c)^{3}$

we can convert it to the form $a^{3} - b^{3}$ as shown below

$(3a)^{3} - (b-c)^{3}$

now expand it and try