Question

Factorise = 27k3 +64k3​

Answer 1

Answer:

13*7*k*k*k

Step-by-step explanation:

27k³+64k³  

= (3k)³+(4k)³

$a^{3} +b^3 = (a+b)(a^2+b^2-ab)$

=> (3k)³+(4k)³

     = (3k+4k)( (3k)²+(4k)²-(3k)(4k) )

     = (7k)( 9k²+16k²-12k² )

     = (7k)( 13k²)

     = 13*7*k*k*k

___________________________________________

method without using formula:

27k³+64k³   = 91k³

                    = 13*7*k³

                    = 13*7*k*k*k

___________________________________________