Math, asked by gurdev49, 9 months ago

factorise 27m^3-343n^3​

Answers

Answered by ayush1211k
10

Answer:

27m^3-343n^3

(3m)^3-(7n)^3

(3m-7n){(3m)^2+3n×7n+(7n)^2}

(3m-7n)(3m+7n)^2

(3m-7n)(3m+7n)(3m+7n)

I think it's help you

Answered by Anonymous
8

\boxed{\huge{\bf{\purple{ANSWER:}}}}

Hello Dear User__________

Here is Your Answer...!!

____________________

Step by step solution:

we \ have \ to \ factorise \ it.\\\\Let \ us \ do\\\\27m^3-343n^3\\\\Using \ identity\\\\a^3-b^3=(a-b)(a^2+ab+b^2)\\\\(27m^3-343n^3)=(2m)^3-(7n)^3\\\\(27m^3-343n^3)=(2m-7n)((2m)^2+2m\times7n+(7n)^2)\\\\(27m^3-343n^3)=(2m-7n)(4m^2+14mn+49n^2)

Hope it is clear to you.


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