Math, asked by iqra1828, 4 days ago

factorise 27m^3-729n^3​

Answers

Answered by drssagrawal
1

Answer:

27m^3-729n^3​

=27X{m^3-27n^3​}

=27X {m^3-(3n)^3​}

=27X{(m-3n)(m^2+mX3n+(3n)^2)}

=3X3X3X(m-3n)(m^2+3mn+9n^2)

Step-by-step explanation:

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