factorise 27m3-216n3
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We know that,
a³ – b³ = (a – b) (a² + b² + ab)
27m3 – 216n3 = 27 (m³ – 8n³) [By taking out the common factor 27]
= 27 [m³ – (2n)³]
Here, a = m and b = 2n
Now, substituting in the above formula, we get
27 [m³ – (2n)³] = 27 {(m – 2n) [m² + m(2n) + (2n)²]}
= 27 (m – 2n) (m² + 2mn + 4n²)
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