Math, asked by faizazahid, 4 months ago

factorise
27m³- 64n³​

Answers

Answered by shaiksumera005
2

Answer:

I hope this is to be factorized.

27m³ + 64n³

3³m³ + 4³n³

(3m)³ + (4n)³

( 3m + 4n ) [ (3m)² - 12mn + (4n)² ]

( 3m + 4n ) [ 9m² - 12mn + 16n² ]

Answered by dangerousqueen01
3

 \sf\red{ 27m³- 64n³ } \\  \sf \red {={(3m)}^{3} -  {(4n)}^{3} } \\  \sf\red{ = (3m - 4n) [{(3m)}^{2} + 3m.4n +  {(4n)}^{2}] }\\  \sf\red{ = (3m - 4n)(9 {m}^{2}  + 12mn + 16 {n}^{2} }

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