Question

factorise 27p^3 + 8q^3 + 54p^2q +36pq^2

Answer 1

Answer:

$27 {p}^{3 \: } + 8 {q}^{3} + 54 {p}^{2} q \: + 36p {q}^{2}$

$(3 {p})^{3} +( 2 {q})^{3} + 3 \times 3p \times 2q(3p \: + 2q)$

$({3p + 2q})^{3}$

Step-by-step explanation:

Here the formula used is:-

$({a \: + b})^{3} = {a}^{3} + {b}^{3} + 3 \times a \times b(a \: + b)$