Question

factorise 27p cube+1/64q cube+27p square/4q+9p16q square

Answer 1

heya, here is your answer

using identity :

$( {x + y)}^{3} = {x}^{3} + {y}^{3} + 3 {x}^{2}y + 3x {y}^{2}$

(3p)³ + (1/4q)³ + 3 × (3p)² ×1/4q + 3×3p× (1/4q)²

=> (3p + 1/4q)³

= (3p+1/4q)(3p+1/4q)(3p+1/4q)

hope it helps :))