factorise 27p cube +q cube
Answers
Answered by
7
HEY....
27p^3 + q^3
= (3p)^3 + (q)^3
According to the formula , a^3 + b^3
= (3p)^3. + (q)^3 =
(3p + q) [ (3p)^2 - 3p*q+ q^2]
= (3p + q) ( 9p^2 - 3pq + q^2).
27p^3 + q^3
= (3p)^3 + (q)^3
According to the formula , a^3 + b^3
= (3p)^3. + (q)^3 =
(3p + q) [ (3p)^2 - 3p*q+ q^2]
= (3p + q) ( 9p^2 - 3pq + q^2).
Answered by
5
27p^3+q^3
=(3p)^3+q^3
=(3p+q)(9p^2-3pq+q^2)
=(3p)^3+q^3
=(3p+q)(9p^2-3pq+q^2)
Similar questions
Think of 27 as 3 3. Then this is a sum of cubes and we can apply the sum of cubes formula:
a 3 + b 3 = (a + b) (a 2 − a b + b 2 ).
Substituting a = x and b = 3 into the formula yields:
x 3 + 27 = (x + 3) (x 2 − 3 x + 9).