Question

Factorise
27p³-1/216-9/2p²+1/4p​

Answer 1

Answer:

27p^3 - 1/216 - 9/2p^2 + 1/4p

= (3p)^3 - (1/6)^3 - 9/2p^2 + 1/4p

= (3p - 1/6)[(3p)^2 + p/2 + 1/36)] - (3p/2)(3p - 1/6)

= (3p - 1/6)(9p^2 + p/2 + 1/36 - 3p/2)

= (3p - 1/6)(9p^2 - 2p/2 + 1/36)

= (3p - 1/6)(9p^2 - p + 1/36)

Answer 2

Step-by-step explanation:

3p^3 - 1/6-3/2p^2+1/4p

it forms an identity

(a-b)^3

so the answer is - (3p-1/6)^3

or

(3p-1/6)(3p-1/6)(3p-1/6)

hope it will help you..................

mark my answer as BRAINLLIEST