Math, asked by Yogesh9809, 9 months ago

Factorise:
27x^3+125y^3+135x^2y +225xy2

Answers

Answered by Anonymous
1

Answer:

(3x +5y)^3

Step-by-step explanation:

27x^3+125y^3+135x^2y +225xy2

= (3x)^3 + (5y)^3 + 3(3x)(5)[3x + 5y]

= (3x +5y)^3

Answered by khairnarsanskriti
1

= 27 x^3 + 125y^3 + 135x^2y + 225xy^2

= (3x)^3 + (5y)^3 + 3( 3x)(5y) [ (3x+5y) ]

= (3x)^3 + (5y)^3 + 45xy ( 3x+5y)

= ( 3x+5y ) ^3

= (3x+5y) (3x+5y) (3x+5y)

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