Factorise 27x^3 - 1728y^3
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Answer:
=(3x+7y)(9x^2-21xy+49y^2)
27x^3+343y^3
=(3x)^3+(7y)^3
Using the formula
a^3+b^3=(a+b)(a^2-ab+b^2)
the given expression becomes
=(3x+7y)(3x)^2-3x*7y+(7y)^2
=(3x+7y)(9x^2-21xy+49y^2)
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