Question

Factorise 27x^3-(3x-y)^3

Answer 1

(3x)^3-(3x-y)^3
= [3x-(3x-y)][(3x)^2+3x(3x-y)+(3x-y)^2]
=(3x-3x+y)[9x^2+9x^2-3xy+9x^2-6xy+y2]
=(y)[27x^2-9xy+y^2]

Answer 2

(3x)^3-(3x-y)^3

= [3x-(3x-y)][(3x)^2+3x(3x-y)+(3x-y)^2]

=(3x-3x+y)[9x^2+9x^2-3xy+9x^2-6xy+y2]

=(y)[27x^2-9xy+y^2]

Hope you like the answer