Question

factorise 27x^3-63x^2+49x-343/27

step by step explanation
HURRY PLEASE​

Answer 1

Answer:

[3x−73][3x−73][3x−73]

Step-by-step explanation:

(a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3

Compare 27x^3 - 63x^2 + 49x - 343/27 to a^3 - 3a^2b + 3ab^2 - b^3

We can deduce that 27x3 = a^3 or (3x)3 = a^3

∴ a = 3x

And 343/27 = b^3 or [73]^3 = b^3

∴ b = 73

So, 27x3 - 63x2 + 49x - 34327 = (3x)3 - 3(3x)2 73 + 3(3x)[73]^2 - [73]^3

= [3x−73]^3

Hence, 27x^3 - 63x^2 + 49x - 343/27 factorizes as [3x−73][3x−73][3x−73]