Question

Factorise : 27x^3-64-108x^2+144x​

Answer 1

Answer:

$27x^3-64-108x^2+144x\\= \left(3x-4\right)\frac{27x^3-108x^2+144x-64}{3x-4}\\= 9x^2-24x+16\\= \left(3x-4\right)\left(3x-4\right)\left(3x-4\right)\\= \left(3x-4\right)^3$

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