Question

Factorise:27x ^3+y^3+z^3-9xyy

Answer 1

Answer:

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Explanation:

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Answer 2

Explanation:

27x³+ y³+ z³– 9xyz = (3x)³ + y³ + z³– 3 × 3xyz

Using identity,

x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z2 – xy – yz – xz)

27x^3 + y^3 + z^3 – 9xyz

= (3x + y + z) {(3x)^2 + y^2 + z^2 – 3xy – yz – 3xz}

= (3x + y + z) (9x2 + y^2 + z^2 – 3xy – yz – 3xz)