Question

factorise: 27x^3+y^3+z^3-9xyz​

Answer 1

Answer:

(3x+y+z)(9x^2+y^2+z^2-3xy-yz-3xz)

Answer 2

Answer:

( 3x^3)+(-y)^3+(z)^3-3(3x)(-y)(z)

Step-by-step explanation:

27^3-y^3+z^3+9xyz

therefore x^3+(-y^3)+(z)^3-3xyz

( 3x^3)+(-y)^3+(z)^3-3(3x)(-y)(z) answer

I hope it is helpfull to you