Question

factorise = 27x^3+y^3+z^3-9xyz​

Answer 1

Answer:

${3x}^{2} + {y}^{2} + {z}^{2} - 3 \times 3x \times y \times z \\ \\ = \frac{1}{2} (3x + y + z)( {x - y}^{2} ) + {y - z}^{2} + {z - x}^{2} )$

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Answer 2

Answer:

According to question:-

$3 {x}^{</strong><strong>3</strong><strong>} + {y}^{</strong><strong>3</strong><strong>} + {z}^{</strong><strong>3</strong><strong>} - 3 \times (3x)(y)(z)$

$= (3x + y + z)( {x}^{2} + {y}^{2} + {z}^{2} - xy - yz - zx)$

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