Question

factorise 27x^3+y^3+z^3-9xyz
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Answer 1

Answer:

$(3x + y + z)(9 {x}^{2} + {y}^{2} + {z}^{2} - 6xy - 2yz - 6xz)$

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Answer 2

Answer:

$\huge\underline \mathfrak\blue{❥︎Answer}$

$→ \: 27 {x}^{3} + {y}^{3} + {z}^{3} -9xyz \\ = ({3x}^{3})+ {y}^{3} + {z}^{3} -3(3x)yz \\ =(3x+y + z)(9 {x}^{2} + {y}^{2} + {z}^{2} -3xy-yz-3zx)$