Question

Factorise 27x cube -1/216 -9/2x square +1/4x

Answer 1

$27 {x}^{3} - \frac{1}{216} - \frac{9}{2} {x}^{2} + \frac{1}{4}x \\ \\ = > {(3x)}^{3} - {( \frac{1}{6} )}^{3} - 3 {(3x)}^{2} ( \frac{1}{6} ) + 3(3x) {( \frac{1}{6}) }^{2} \\ \\ as \: we \: know \: that \: {(a - b)}^{3} = {a}^{3} - {b}^{3} - 3 {a}^{2} b + 3a {b}^{2} \: here \: a = 3x \: and \: b = \frac{1}{6} \\ \\ = > {(3x - \frac{1}{6}) }^{3}$

Answer 2

Answer:

Step-by-step explanation:

(3x-1/6)³