Factorise 27x²+64 (class 9)
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The equation can't be factorised.
If it's 27x³ instead of 27x², then it can be, otherwise it can't.
Let's consider 27x³ + 64
→ 27x³ + 64
→ (3x)³ + (4)³
→ (3x+4)[(3x)²+(4)²-3x × 4)] ...[ since, a³+b³=(a+b)(a²+b²-ab) ]
→ (3x+4)(9x²+16-12x)
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