factorise 27x3- 512y3
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1
Answer:
See this yr
Step-by-step explanation:
Rewrite 27x3 27 x 3 as (3x)3 ( 3 x ) 3 . Rewrite 512y3 512 y 3 as (8y)3 ( 8 y ) 3 . Since both terms are perfect cubes, factor using the sum of cubes formula, a3+b3=(a+b)(a2−ab+b2) a 3 + b 3 = ( a + b ) ( a 2 - a b + b 2 ) where a=3x a = 3 x and b=8y b = 8 y .
Answered by
0
Answer:
Rewrite 27x3 27 x 3 as (3x)3 ( 3 x ) 3 . Rewrite 512y3 512 y 3 as (8y)3 ( 8 y ) 3 . Since both terms are perfect cubes, factor using the sum of cubes formula, a3+b3=(a+b)(a2−ab+b2) a 3 + b 3 = ( a + b ) ( a 2 - a b + b 2 ) where a=3x a = 3 x and b=8y b = 8 y . Simplify.
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