Question

Factorise 27x³+8y³-z³+18xyz using suitable identity​

Answer 1

Step-by-step explanation:

We will use the algebraic identity: x³ + y³ + z³ - 3xyz = (x + y + z)(x² + y² + z² - xy - yz - zx)

• The given expression 27x³ + y³ + z³ - 9xyz can be written as (3x)³ +(y)³ +(z)³ - 3(3x)(y)(z)

• By using the identity x³ + y³ + z³ - 3xyz = (x + y + z)(x² + y² + z² - xy - yz - zx)

• We can write: (3x)³ + (y)³ + (z)² - 3(3x)(y)(z) = (3x + y + z)[(3x)² + ( y)² + (z)² - (3x)( y) - yz - (z)(3x)]

• Hence, 27x³ + y³ + z³ - 9xyz = (3x + y + z)(9x² + y² + z² - 3xy - yz - 3zx)

hope this helps you

Answer 2

Refer the above attachment :)