factorise 27x3+y3+2 cube -9xyz
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Answered by
2
Answer:
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0+b3 =
a3+b3
Check : 27 is the cube of 3
Check : x3 is the cube of x1
Check : y3 is the cube of y1
Factorization is :
(3x - y) • (9x2 + 3xy + y2)
Answered by
0
Answer:
=5.436564bcu+27x3−9xyz+y3
Step-by-step explanation:
= 27x3+y3+2cub(2.718282)−9xyz
= 27x3+y3+5.436564bcu+−9xyz
=5.436564bcu+27x3−9xyz+y3
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