Question

Factorise 27x3+ y3+ z3-9 xyz

Answer 1

27x3+y3+z3-9xyz

(3x)3+y3+z3-9xyz

(a3+b3+c3)=(a+b+c)(a2+b2+c2-ab-bc-cb)+3abc

a=3x
b=y
c=z
(3x+y+z)(9x2+y2+z2-3xy-yz-yz-3.3x.y.z)

(3x+y+z)(9x2+y2+z2-3xy-3xz-3xz)+3.3x.y.z-9xyz

(3x+y+z)(9x2+y2+z2-3xy-3xz-yz)

.9xyz and -9xyz both hv oppste sign so become zero

Answer 2

Explanation:

i hope you will understand this question