Question

Factorise :
27x3 +y3+z3-9xyz

Answer 1

Answer:

$= 27 {x}^{3} + {y}^{3} + {z}^{3 } - 9xyz \\ = {(3x)}^{3} + {y}^{3} + {z}^{3} - 3.3x .y.z \\ = (3x + y + z)(9 {x}^{2} + {y}^{2} + {z}^{2} - 3xy -yz - 3zx )$