Question

factorise 27x³+y³+z³-9xyz​

Answer 1

Answer:

$=[3X+Y+Z][9X2+Y2+Z2−3XY−YZ−3XZ]$

Answer 2

Answer:

SOLUTION:-

Given 27x³±y³±z³-9xyz

=(3x)³±(y)³±(z)³-3(3x)(y)(z)

=(3x±y±z)

[(3x)²±y²±z²-(3x)(y)-

(y)(z)-(z)(3x)]

*(x³±y³±z³-3xyz=(x±y±z)

(x²±y²±z²-xy-yz-zx)

=(3x±y±z) (9x²±y²±z²-3xy-yz-3xz)