Question

Factorise 27xcube - 16ycube

Answer 1

Answer:(3x-2.5y)(9x^2+7.5xy +6.25y^2)

Step-by-step explanation:

[Tex] 27x{}^{3} - 16y{}^{3}[/tex]

[Tex](3x){}^{3} - (2.5y){}^{3}[/tex]

(a - b) • (a^2 + ab + b^2)

A=3x B = 2.5y

(3x-2.5y)(9x^2+7.5xy +6.25y^2)

#skb

Answer 2

$\huge{\textbf{ANSWER:}}$

$\boxed{(3x+2\sqrt[3]{2})(9x^2+2.\sqrt[3]{2}+3x.2\sqrt[3]{2})}$

$\textbf{SOLUTION}$

$27x^3-16y^3$
$(3x)^3-(8\times 2)y^3$
$\implies (3x)^3-(2\sqrt[3]{2}y)^3$

Use : $\bf{a^3-b^3=(a-b)(a^2+b^2+ab)}$

$\implies (3x+2\sqrt[3]{2}y)(9x^2+2\times \sqrt[3]{2}+3x(2\sqrt[3]{2})$

$\implies ( 3x+2\sqrt[3]{2}y)(9x^2+2.\sqrt[3]{2}+3x.2\sqrt[3]{2})$