Factorise : 27y3 + 125 z3
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
27y^3 + 125z^3
ie [3y]^3 + [5z]^3
we know the formula
x3+y3 = [x+y][x^2-xy+y3}
so,
[3y]^3 + [5z]^3 = [3y+5z] {[3y]^2-3y x 5z + [5z}^2}
= [3y+5z] [9y^2-15yz+25z^2]
therefore, [3y]^3 +[5z]^3 = [3y+5z] [9y^2-15yz+25z^2]
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