Math, asked by kavithakumari, 1 year ago

factorise 27y3+125y3

Answers

Answered by chandraharish
18
27y3+125y3=(3y)3+(5y)3
                    =(3y+5y)(9y2+25y2-15y2)
Answered by littlerose
21
 27y^{3} + 125y^{3}
  =  (3y)^{3} + (5y)^{3}
 Using Formula,  a^{3} + b^{3} = (a + b) (a^{2} - ab + b^{2})
        (3y)^{3} + (5y)^{3}  =(3y + 5y) {(3y)^{2} - 3y*5y - (5y)^{2}}                                             = 9y^{2} + 15y^{2} - 25y^{2}
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