factorise 27y³+125z³ using identity.
hint-(3y)³+(5z)³
Now use identity
= x³+y³
=(x+y)(x²-xy+y²)
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27y³+125z³
= (3y)³+(5z)³
= (3y+5z) {(3y²)+3y×5z +(5z)²}
= (3y+5z) (9y²+15yz+25z²
Step-by-step explanation:
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