Question

factorise 27ycube +125z cube

Answer 1

Factories 27y^3+125z^3
= (3y+5z)^3
= 3y^3+5z^3+3×3y×5z
= 27y^3+125z^3+45yz

Answer 2

27y^3 + 125z^3

(3y)^3 + (5z)^3

(3y + 5z)^3

3y^3 +5z^3 + 3{(3y)(5z)} (3y+5z)

3y^3 +5z^3 + 3{15yz} (3y+5z)

3y^3 +5z^3 + 45yz (3y+5z)

3y^3 + 5z (1+9y)(3y+5z)

i hope this is enough