Factorise: (2a + 1) ^3 + (a – 1)^3
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Answer:
(2a+1)³+(a-1)³
= (2a+1+a-1){(2a+1)²-(2a+1)(a-1)+(a-1)²}
= 3a{4a²+4a+1-(2a²-2a+a-1)+a²-2a+1}
= 3a(5a²-2a+2-2a²+2a-a+1)
= 3a(3a²-a+3)
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