Math, asked by brotheralok, 1 year ago

factorise

(2a+3b)^2-(3b-2b)^2


Muthu2004: I think it is (3b-2a)^2

Answers

Answered by RanjanKumar14
4
★ Hi , there !!★


here is your answer !!


( 2a + 3b )² - ( 3b - 2b ) ²


=> ( 2a + 3b )² - ( b )²


{ a² - b² = ( a+ b ) ( a - b ) } { using this identity }



(2a + 3b + b ) ( 2a + 3b - b )



=> ( 2a + 4b ) ( 2a +2b )


=> 2 ( a + 2b ) ( a + b )



hope it helps you dear !!



thanks!!!
Answered by Muthu2004
3
(2 a+3b)^2-(3b-2a) ^2
=((2a)^2+2*2a*3b+(3b)^2)-((3b)^2-2*3b*2a+(2a)^2)
=4a^2+12ab+9b^2-(9b^2-12ab+4a^2)
=4a^2+12ab+9b^2-9b^2+12ab-4a^2
=24ab

Muthu2004: Mark as brainliest
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