factorise
(2a+3b)^2-(3b-2b)^2
Muthu2004:
I think it is (3b-2a)^2
Answers
Answered by
4
★ Hi , there !!★
here is your answer !!
( 2a + 3b )² - ( 3b - 2b ) ²
=> ( 2a + 3b )² - ( b )²
{ a² - b² = ( a+ b ) ( a - b ) } { using this identity }
(2a + 3b + b ) ( 2a + 3b - b )
=> ( 2a + 4b ) ( 2a +2b )
=> 2 ( a + 2b ) ( a + b )
hope it helps you dear !!
thanks!!!
here is your answer !!
( 2a + 3b )² - ( 3b - 2b ) ²
=> ( 2a + 3b )² - ( b )²
{ a² - b² = ( a+ b ) ( a - b ) } { using this identity }
(2a + 3b + b ) ( 2a + 3b - b )
=> ( 2a + 4b ) ( 2a +2b )
=> 2 ( a + 2b ) ( a + b )
hope it helps you dear !!
thanks!!!
Answered by
3
(2 a+3b)^2-(3b-2a) ^2
=((2a)^2+2*2a*3b+(3b)^2)-((3b)^2-2*3b*2a+(2a)^2)
=4a^2+12ab+9b^2-(9b^2-12ab+4a^2)
=4a^2+12ab+9b^2-9b^2+12ab-4a^2
=24ab
=((2a)^2+2*2a*3b+(3b)^2)-((3b)^2-2*3b*2a+(2a)^2)
=4a^2+12ab+9b^2-(9b^2-12ab+4a^2)
=4a^2+12ab+9b^2-9b^2+12ab-4a^2
=24ab
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