Question

Factorise
(2a + 3b)^2 - 4c^2
​

Answer 1

Step-by-step explanation:

(2a + 3b)²- 4c²

= (2a+3b)²-(2c)²

= [(2a+3b)+2c] [(2a+3b)-2c]

= (2a+3b+2c) (2a+3b-2c)

We have used the identity,

x²-y² = (x+y)(x-y)

Here, (2a+3b) = x & 2c = y.

Answer 2

Answer:

(2a+3b)^2 - 4c ^2

(2a+3b) ^2 - (2c)^2

[(2a + 3b) +2c] [(2a+3b) - 2c]

(2a+3b+2c) (2a+3b-2c)