Question

Factorise (2a + 3b)^2 - 4c^2​

Answer 1

QUESTION :

$factorise \: \: {(2a + 3b)}^{2} - 4 {c}^{2}$

ANSWER :

${(2a + 3b)}^{2} - 4 {c}^{2}$

$(2a + 3b)(2a + 3b) - 4 {c}^{2}$

$2a(2a + 3b) + 3b(2a + 3b) - 4 {c}^{2}$

$4 {a }^{2} + 6ab + 3b(2a + 3b) - 4 {c}^{2}$

$4 {a}^{2} + 6ab + 6ab + 9 {b}^{2} - 4 {c}^{2}$

$4 {a}^{2} + 12ab + 9 {b}^{2} - 4 {c}^{2}$

❤️@vishnu❤️