Question

factorise (2a+3b)²-4c²

Answer 1

Here's the Factorisation :

$({2a + 3b)}^{2} - 4 {c}^{2} \\ we \: know \: that \\ {x}^{2} - {y}^{2} = (x - y)(x + y) \\ \\ so \\ {(2a + 3b)}^{2} - 4 {c}^{2} \\ \\ = ({2b + 3b)}^{2} - {(2c)}^{2} \\ \\ = (2b + 3b + 2c)(2b + 3b - 2c)$

Thus factorized

Answer 2

Answer:

(2a+3b)²-4c²

=(2b+3b²-(x)²

=(2b+3b+2c)(2b+3b-2c)