Math, asked by gaurik0000, 9 months ago

Factorise (2a+3b)²+8(2a+3b)+15



Pls tell the answer​

Answers

Answered by kartik2507
1

Step-by-step explanation:

let 2a + 3b = x

 {x}^{2}  + 8x + 15  = 0\\  {x}^{2}  + 5x + 3x + 15 = 0 \\ x(x + 5) + 3(x + 5) = 0 \\ (x + 5)(x + 3) = 0 \\ substitute \: x = 2a + 3b \\ (2a + 3b + 5)(2a + 3b + 3)

verification

(2a + 3b + 5)(2a + 3b + 3) \\ 4 {a}^{2}  + 6ab + 6a + 6ab + 9 {b}^{2}  + 9b + 10a + 15b + 15 \\ 4 {a}^{2}  + 12ab + 9 {b}^{2}  + 16a + 24b + 15 \\  {(2a)}^{2}  + 12ab +  {(3b)}^{2}  + 8(2a + 3b) + 15 \\  {(2a + 3b)}^{2}  + 8(2a + 3b) + 15

hope you get your answer

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