Question

factorise (2a+3b)^2-9c^2​

Answer 1

Answer:

4a(a+3b)+9(b+c)(b-c).

Step-by-step explanation:

= (2a+3b)²-9c²

= 4a²+9b²+12ab-9c²

= 4a²+12ab+9b²-9c²

= 4a(a+3b)+9(b²-c²)

= 4a(a+3b)+9(b+c)(b-c)

Hope this helps.

Answer 2

Step-by-step explanation:

(2a+3b)² -9c

(2a+3b) ² - 9c²

(2a+3b-3c) (2a-3b+3c)