Math, asked by makhanupfs, 7 months ago

factorise:
(2a+3b)(2a+3b)-4c*4c​

Answers

Answered by vijaysahyahoo
2

Answer:

(2a+3b)(2a+3b)–4c*4c

(2a+3b)²–(4c)²

{(2a+3b)+4c}{(2a+3b)–4c}

(2a+3b+4c)(2a+3b–4c)

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