factorise:
(2a+3b)(2a+3b)-4c*4c
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Answer:
(2a+3b)(2a+3b)–4c*4c
(2a+3b)²–(4c)²
{(2a+3b)+4c}{(2a+3b)–4c}
(2a+3b+4c)(2a+3b–4c)
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